Solve for x 3(x-1)=2(x+1)

$3 (x - 1) = 2 (x + 1)$

Simplify $3 (x - 1)$ .

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Apply the distributive property.

$3 x + 3 \cdot - 1 = 2 (x + 1)$

Multiply $3$ by $- 1$ .

$3 x - 3 = 2 (x + 1)$

Simplify $2 (x + 1)$ .

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Apply the distributive property.

$3 x - 3 = 2 x + 2 \cdot 1$

Multiply $2$ by $1$ .

$3 x - 3 = 2 x + 2$

Move all terms containing $x$ to the left side of the equation.

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Subtract $2 x$ from both sides of the equation.

$3 x - 3 - 2 x = 2$

Subtract $2 x$ from $3 x$ .

$x - 3 = 2$

Move all terms not containing $x$ to the right side of the equation.

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Add $3$ to both sides of the equation.

$x = 2 + 3$

Add $2$ and $3$ .

$x = 5$

Solve for x 3(x-1)=2(x+1)

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