Solve for x -3(3x-5)=6x

$- 3 (3 x - 5) = 6 x$

Simplify $- 3 (3 x - 5)$ .

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Apply the distributive property.

$- 3 (3 x) - 3 \cdot - 5 = 6 x$

Multiply.

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Multiply $3$ by $- 3$ .

$- 9 x - 3 \cdot - 5 = 6 x$

Multiply $- 3$ by $- 5$ .

$- 9 x + 15 = 6 x$

Move all terms containing $x$ to the left side of the equation.

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Subtract $6 x$ from both sides of the equation.

$- 9 x + 15 - 6 x = 0$

Subtract $6 x$ from $- 9 x$ .

$- 15 x + 15 = 0$

Subtract $15$ from both sides of the equation.

$- 15 x = - 15$

Divide each term by $- 15$ and simplify.

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Divide each term in $- 15 x = - 15$ by $- 15$ .

$\frac{- 15 x}{- 15} = \frac{- 15}{- 15}$

Cancel the common factor of $- 15$ .

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Cancel the common factor.

$\frac{- 15 x}{- 15} = \frac{- 15}{- 15}$

Divide $x$ by $1$ .

$x = \frac{- 15}{- 15}$

Divide $- 15$ by $- 15$ .

$x = 1$

Solve for x -3(3x-5)=6x

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