Find Trig Functions Using Identities sec(theta)=3 , tan(theta)>0

$\sec (θ) = 3$ , $\tan (θ) > 0$

The $t a n$ function is positive in the $f i r s t$ and $t h i r d$ quadrants. The $s e c$ function is positive in the $f i r s t$ and $f o u r t h$ quadrants. The set of solutions for $θ$ are limited to the $f i r s t (q u a d r a n t)$ since that is the only quadrant found in both sets.

Solution is in first quadrant.

Use the definition of secant to find the known sides of the unit circle right triangle. The quadrant determines the sign on each of the values.

$\sec (θ) = \frac{hypotenuse}{adjacent}$

Find the opposite side of the unit circle triangle. Since the adjacent side and hypotenuse are known, use the Pythagorean theorem to find the remaining side.

$Opposite = \sqrt{{hypotenuse}^{2} - {adjacent}^{2}}$

Replace the known values in the equation.

$Opposite = \sqrt{{(3)}^{2} - {(1)}^{2}}$

Simplify $\sqrt{{(3)}^{2} - {(1)}^{2}}$ .

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Raise $3$ to the power of $2$ .

Opposite $= \sqrt{9 - {(1)}^{2}}$

One to any power is one.

Opposite $= \sqrt{9 - 1 \cdot 1}$

Multiply $- 1$ by $1$ .

Opposite $= \sqrt{9 - 1}$

Subtract $1$ from $9$ .

Opposite $= \sqrt{8}$

Rewrite $8$ as $2^{2} \cdot 2$ .

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Factor $4$ out of $8$ .

Opposite $= \sqrt{4 (2)}$

Rewrite $4$ as $2^{2}$ .

Opposite $= \sqrt{2^{2} \cdot 2}$

Pull terms out from under the radical.

Opposite $= 2 \sqrt{2}$

Find the value of sine.

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Use the definition of sine to find the value of $\sin (θ)$ .

$\sin (θ) = \frac{opp}{hyp}$

Substitute in the known values.

$\sin (θ) = \frac{2 \sqrt{2}}{3}$

Find the value of cosine.

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Use the definition of cosine to find the value of $\cos (θ)$ .

$\cos (θ) = \frac{adj}{hyp}$

Substitute in the known values.

$\cos (θ) = \frac{1}{3}$

Find the value of tangent.

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Use the definition of tangent to find the value of $\tan (θ)$ .

$\tan (θ) = \frac{opp}{adj}$

Substitute in the known values.

$\tan (θ) = \frac{2 \sqrt{2}}{1}$

Divide $2 \sqrt{2}$ by $1$ .

$\tan (θ) = 2 \sqrt{2}$

Find the value of cotangent.

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Use the definition of cotangent to find the value of $\cot (θ)$ .

$\cot (θ) = \frac{adj}{opp}$

Substitute in the known values.

$\cot (θ) = \frac{1}{2 \sqrt{2}}$

Simplify the value of $\cot (θ)$ .

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Multiply $\frac{1}{2 \sqrt{2}}$ by $\frac{\sqrt{2}}{\sqrt{2}}$ .

$\cot (θ) = \frac{1}{2 \sqrt{2}} \cdot \frac{\sqrt{2}}{\sqrt{2}}$

Combine and simplify the denominator.

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Multiply $\frac{1}{2 \sqrt{2}}$ and $\frac{\sqrt{2}}{\sqrt{2}}$ .

$\cot (θ) = \frac{\sqrt{2}}{2 \sqrt{2} \sqrt{2}}$

Move $\sqrt{2}$ .

$\cot (θ) = \frac{\sqrt{2}}{2 (\sqrt{2} \sqrt{2})}$

Raise $\sqrt{2}$ to the power of $1$ .

$\cot (θ) = \frac{\sqrt{2}}{2 (\sqrt{2} \sqrt{2})}$

Raise $\sqrt{2}$ to the power of $1$ .

$\cot (θ) = \frac{\sqrt{2}}{2 (\sqrt{2} \sqrt{2})}$

Use the power rule $a^{m} a^{n} = a^{m + n}$ to combine exponents.

$\cot (θ) = \frac{\sqrt{2}}{2 {\sqrt{2}}^{1 + 1}}$

Add $1$ and $1$ .

$\cot (θ) = \frac{\sqrt{2}}{2 {\sqrt{2}}^{2}}$

Rewrite ${\sqrt{2}}^{2}$ as $2$ .

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Rewrite $\sqrt{2}$ as $2^{\frac{1}{2}}$ .

$\cot (θ) = \frac{\sqrt{2}}{2 {(2^{\frac{1}{2}})}^{2}}$

Apply the power rule and multiply exponents, ${(a^{m})}^{n} = a^{m n}$ .

$\cot (θ) = \frac{\sqrt{2}}{2 \cdot 2^{\frac{1}{2} \cdot 2}}$

Combine $\frac{1}{2}$ and $2$ .

$\cot (θ) = \frac{\sqrt{2}}{2 \cdot 2^{\frac{2}{2}}}$

Cancel the common factor of $2$ .

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Cancel the common factor.

$\cot (θ) = \frac{\sqrt{2}}{2 \cdot 2^{\frac{2}{2}}}$

Divide $1$ by $1$ .

$\cot (θ) = \frac{\sqrt{2}}{2 \cdot 2}$

Evaluate the exponent.

$\cot (θ) = \frac{\sqrt{2}}{2 \cdot 2}$

Multiply $2$ by $2$ .

$\cot (θ) = \frac{\sqrt{2}}{4}$

Find the value of cosecant.

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Use the definition of cosecant to find the value of $\csc (θ)$ .

$\csc (θ) = \frac{hyp}{opp}$

Substitute in the known values.

$\csc (θ) = \frac{3}{2 \sqrt{2}}$

Simplify the value of $\csc (θ)$ .

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Multiply $\frac{3}{2 \sqrt{2}}$ by $\frac{\sqrt{2}}{\sqrt{2}}$ .

$\csc (θ) = \frac{3}{2 \sqrt{2}} \cdot \frac{\sqrt{2}}{\sqrt{2}}$

Combine and simplify the denominator.

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Multiply $\frac{3}{2 \sqrt{2}}$ and $\frac{\sqrt{2}}{\sqrt{2}}$ .

$\csc (θ) = \frac{3 \sqrt{2}}{2 \sqrt{2} \sqrt{2}}$

Move $\sqrt{2}$ .

$\csc (θ) = \frac{3 \sqrt{2}}{2 (\sqrt{2} \sqrt{2})}$

Raise $\sqrt{2}$ to the power of $1$ .

$\csc (θ) = \frac{3 \sqrt{2}}{2 (\sqrt{2} \sqrt{2})}$

Raise $\sqrt{2}$ to the power of $1$ .

$\csc (θ) = \frac{3 \sqrt{2}}{2 (\sqrt{2} \sqrt{2})}$

Use the power rule $a^{m} a^{n} = a^{m + n}$ to combine exponents.

$\csc (θ) = \frac{3 \sqrt{2}}{2 {\sqrt{2}}^{1 + 1}}$

Add $1$ and $1$ .

$\csc (θ) = \frac{3 \sqrt{2}}{2 {\sqrt{2}}^{2}}$

Rewrite ${\sqrt{2}}^{2}$ as $2$ .

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Rewrite $\sqrt{2}$ as $2^{\frac{1}{2}}$ .

$\csc (θ) = \frac{3 \sqrt{2}}{2 {(2^{\frac{1}{2}})}^{2}}$

Apply the power rule and multiply exponents, ${(a^{m})}^{n} = a^{m n}$ .

$\csc (θ) = \frac{3 \sqrt{2}}{2 \cdot 2^{\frac{1}{2} \cdot 2}}$

Combine $\frac{1}{2}$ and $2$ .

$\csc (θ) = \frac{3 \sqrt{2}}{2 \cdot 2^{\frac{2}{2}}}$

Cancel the common factor of $2$ .

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Cancel the common factor.

$\csc (θ) = \frac{3 \sqrt{2}}{2 \cdot 2^{\frac{2}{2}}}$

Divide $1$ by $1$ .

$\csc (θ) = \frac{3 \sqrt{2}}{2 \cdot 2}$

Evaluate the exponent.

$\csc (θ) = \frac{3 \sqrt{2}}{2 \cdot 2}$

Multiply $2$ by $2$ .

$\csc (θ) = \frac{3 \sqrt{2}}{4}$

This is the solution to each trig value.

$\sin (θ) = \frac{2 \sqrt{2}}{3}$

$\cos (θ) = \frac{1}{3}$

$\tan (θ) = 2 \sqrt{2}$

$\cot (θ) = \frac{\sqrt{2}}{4}$

$\sec (θ) = 3$

$\csc (θ) = \frac{3 \sqrt{2}}{4}$

Find Trig Functions Using Identities sec(theta)=3 , tan(theta)>0

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