Find the Integral (x+1)/x

$\frac{x + 1}{x}$

Split the fraction into multiple fractions.

$\int \frac{x}{x} + \frac{1}{x} d x$

Split the single integral into multiple integrals.

$\int \frac{x}{x} d x + \int \frac{1}{x} d x$

Cancel the common factor of $x$ .

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Cancel the common factor.

$\int \frac{x}{x} d x + \int \frac{1}{x} d x$

Divide $1$ by $1$ .

$\int 1 d x + \int \frac{1}{x} d x$

Since $1$ is constant with respect to $x$ , move $1$ out of the integral.

$x + C + \int \frac{1}{x} d x$

The integral of $\frac{1}{x}$ with respect to $x$ is $\ln (| x |)$ .

$x + C + \ln (| x |) + C$

Simplify.

$x + \ln (| x |) + C$

Find the Integral (x+1)/x

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