Find the Integral sin(x)cos(x)

$\sin (x) \cos (x)$

Let $u = \sin (x)$ . Then $d u = \cos (x) d x$ , so $\frac{1}{\cos (x)} d u = d x$ . Rewrite using $u$ and $d$ $u$ .

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Let $u = \sin (x)$ . Find $\frac{d u}{d x}$ .

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Differentiate $\sin (x)$ .

$\frac{d}{d x} [\sin (x)]$

The derivative of $\sin (x)$ with respect to $x$ is $\cos (x)$ .

$\cos (x)$

Rewrite the problem using $u$ and $d u$ .

$\int u d u$

By the Power Rule, the integral of $u$ with respect to $u$ is $\frac{1}{2} u^{2}$ .

$\frac{1}{2} u^{2} + C$

Replace all occurrences of $u$ with $\sin (x)$ .

$\frac{1}{2} \sin^{2} (x) + C$

Find the Integral sin(x)cos(x)

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