Find the Derivative – d/dx y=(arctan(6x))^2

$y = {(\arctan (6 x))}^{2}$

Differentiate using the chain rule, which states that $\frac{d}{d x} [f (g (x))]$ is $f' (g (x)) g' (x)$ where $f (x) = x^{2}$ and $g (x) = \arctan (6 x)$ .

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To apply the Chain Rule, set $u_{1}$ as $\arctan (6 x)$ .

$\frac{d}{d u_{1}} [{u_{1}}^{2}] \frac{d}{d x} [\arctan (6 x)]$

Differentiate using the Power Rule which states that $\frac{d}{d u_{1}} [{u_{1}}^{n}]$ is $n {u_{1}}^{n - 1}$ where $n = 2$ .

$2 u_{1} \frac{d}{d x} [\arctan (6 x)]$

Replace all occurrences of $u_{1}$ with $\arctan (6 x)$ .

$2 \arctan (6 x) \frac{d}{d x} [\arctan (6 x)]$

Differentiate using the chain rule, which states that $\frac{d}{d x} [f (g (x))]$ is $f' (g (x)) g' (x)$ where $f (x) = \arctan (x)$ and $g (x) = 6 x$ .

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To apply the Chain Rule, set $u_{2}$ as $6 x$ .

$2 \arctan (6 x) (\frac{d}{d u_{2}} [\arctan (u_{2})] \frac{d}{d x} [6 x])$

The derivative of $\arctan (u_{2})$ with respect to $u_{2}$ is $\frac{1}{1 + {u_{2}}^{2}}$ .

$2 \arctan (6 x) (\frac{1}{1 + {u_{2}}^{2}} \frac{d}{d x} [6 x])$

Replace all occurrences of $u_{2}$ with $6 x$ .

$2 \arctan (6 x) (\frac{1}{1 + {(6 x)}^{2}} \frac{d}{d x} [6 x])$

Differentiate.

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Factor $6$ out of $6 x$ .

$2 \arctan (6 x) (\frac{1}{1 + {(6 (x))}^{2}} \frac{d}{d x} [6 x])$

Combine fractions.

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Simplify the expression.

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Apply the product rule to $6 (x)$ .

$2 \arctan (6 x) (\frac{1}{1 + 6^{2} x^{2}} \frac{d}{d x} [6 x])$

Raise $6$ to the power of $2$ .

$2 \arctan (6 x) (\frac{1}{1 + 36 x^{2}} \frac{d}{d x} [6 x])$

Combine $\frac{1}{1 + 36 x^{2}}$ and $2$ .

$\frac{2}{1 + 36 x^{2}} \arctan (6 x) \frac{d}{d x} [6 x]$

Combine $\frac{2}{1 + 36 x^{2}}$ and $\arctan (6 x)$ .

$\frac{2 \arctan (6 x)}{1 + 36 x^{2}} \frac{d}{d x} [6 x]$

Since $6$ is constant with respect to $x$ , the derivative of $6 x$ with respect to $x$ is $6 \frac{d}{d x} [x]$ .

$\frac{2 \arctan (6 x)}{1 + 36 x^{2}} (6 \frac{d}{d x} [x])$

Combine fractions.

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Combine $6$ and $\frac{2 \arctan (6 x)}{1 + 36 x^{2}}$ .

$\frac{6 (2 \arctan (6 x))}{1 + 36 x^{2}} \frac{d}{d x} [x]$

Multiply $2$ by $6$ .

$\frac{12 \arctan (6 x)}{1 + 36 x^{2}} \frac{d}{d x} [x]$

Differentiate using the Power Rule which states that $\frac{d}{d x} [x^{n}]$ is $n x^{n - 1}$ where $n = 1$ .

$\frac{12 \arctan (6 x)}{1 + 36 x^{2}} \cdot 1$

Simplify the expression.

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Multiply $\frac{12 \arctan (6 x)}{1 + 36 x^{2}}$ by $1$ .

$\frac{12 \arctan (6 x)}{1 + 36 x^{2}}$

Reorder terms.

$\frac{12 \arctan (6 x)}{36 x^{2} + 1}$

Find the Derivative – d/dx y=(arctan(6x))^2

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