Find the Area triangle (6ft)(3ft)

 $\begin{array}{r} b = & 3 ft \\ h = & 6 ft \end{array}$

The area of a triangle is equal to $\frac{1}{2}$ the base times the height.

$\frac{1}{2} \cdot (b a s e) \cdot (h e i g h t)$

Substitute the values of the base $b = 3$ and height $h = 6$ into the formula for the area of a triangle.

$\frac{1}{2} \cdot 3 \cdot 6$

Combine $\frac{1}{2}$ and $3$ .

$\frac{3}{2} \cdot 6$

Cancel the common factor of $2$ .

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Factor $2$ out of $6$ .

$\frac{3}{2} \cdot (2 (3))$

Cancel the common factor.

$\frac{3}{2} \cdot (2 \cdot 3)$

Rewrite the expression.

$3 \cdot 3$

Multiply $3$ by $3$ .

$9 {(f t)}^{2}$

Find the Area triangle (6ft)(3ft)

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